What Is The Percent Yield Of C6h5cl

Suppose 39.0 g (C6H6) reacts with an excess of C6H6 + Cl2> C6H5Cl + Hcl (Cl2) and 30.0 g (C6H5CL)? 3

What is the percentage of C6H5Cl?

Thank you very much

Benzene = 39.0 grams / 78.054 grams / mole = 0.500

The ratio of benzene and chlorobenzene is 1: 1.

Chlorobenzene = 0.500

M chlorobenzene = 0.500 mol x 112.559 g / mol = 56.3 g (theoretical output)

% Yield = 30.0 x 100 / 56.3 = 53.3

You can use stoichiometry:

39 g C6H6 x (1 mol ChH6 / 78 g C6H6) x (1 mol C6H5Cl /

1 mol C6H6) x (112 g C6H5Cl / 1 mol C6H5Cl) = 53.57 g. Yield = 30 grams x 100 / 53.57 grams

0.5357 = 53.6 grams C6H5Cl