Integral Of Sec 3x - How To Discuss
Integral Of Sec 3x
Second Integral 3x / Tan 4x? 3
 "Dry 3x / tin 4x dx
= ˆ "1 / [cos 3 x * sin 4 x / cos 4 x] dx
= Cos "cos x dx / sin 4 x dx
Let's go = sin x
du = cos x dx
Cos "cos x / sin 4 x dx = ˆÂ" du / u 4
= ˆ «u (4) You
= u (4 + 1) / (4 + 1)
= 1 / (3u 3)
Replace you with sin x.
= 1 / (3 sins 3 x) + c
= csc 3x / 3 + C
ˆ "(1 / cos 3 (x)) * (cos 4 (x) / sin 4 (x)) dx =
Cos "cos (x) / sin 4 (x) dx =
1 "1 / sin 4 (x) d (sin (x)) =
(1/3) * (1 / sin 3 (x)) + C
Section (x) / tanà  (x)
= Dry (x) stump (x)
= cscó (x) nurture (x)
«Csc³ (x) cradle (x) dx = csc³ (x) / 3 + C
