A 23.6 G Sample Of An Unknown Gas Occupies

A 23.6 g sample of an unknown gas has a volume of 12.0 liters at standard temperature and pressure. What is this gas molecule? 3

STP condition is 1 atm pressure and 273 K temperature.

PV = nRT

P = 1 atm

V = 12 liters

t =?

R = 0.0821 l atm / K / mol

T = 273 K.

1 x 12 = North x 0.0821 x 273

12 = North X 22,413

n = 12 / 22,413 = 0.535

Number de = quantity of gas / gas m molar = 0.535

23.6 / molar gas m = 0.535

Mرller gas = 23.6 / 0.535 = 44.11 g / mol

The molar is CO2.